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Python program to check if year is a leap year or not

Python program to check if year is a leap year or not
1 min read

 # Python program to check if year is a leap year or not


year = 2000


# To get year (integer input) from the user

# year = int(input("Enter a year: "))


# divided by 100 means century year (ending with 00)

# century year divided by 400 is leap year

if (year % 400 == 0) and (year % 100 == 0):

    print("{0} is a leap year".format(year))


# not divided by 100 means not a century year

# year divided by 4 is a leap year

elif (year % 4 ==0) and (year % 100 != 0):

    print("{0} is a leap year".format(year))


# if not divided by both 400 (century year) and 4 (not century year)

# year is not leap year

else:

    print("{0} is not a leap year".format(year))


Run Code

Output


2000 is a leap year

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